Web/API/URLSearchParams/get

The get() method of the URLSearchParams interface returns the first value associated to the given search parameter.

Note: This feature is available in Web Workers.

Syntax

URLSearchParams.get(name)

Parameters

name

The name of the parameter to return.

Return value

A USVString if the given search parameter is found; otherwise, null.

Examples

If the URL of your page is https://example.com/?name=Jonathan&age=18 you could parse out the 'name' and 'age' parameters using:

let params = new URLSearchParams(document.location.search.substring(1));
let name = params.get("name"); // is the string "Jonathan"
let age = parseInt(params.get("age"), 10); // is the number 18

Requesting a parameter that isn't present in the query string will return null:

let address = params.get("address"); // null

Specifications

Specification	Status	Comment
URLThe definition of 'get()' in that specification.	Living Standard	Initial definition.

Browser compatibility

The compatibility table on this page is generated from structured data. If you'd like to contribute to the data, please check out https://github.com/mdn/browser-compat-data and send us a pull request.

Update compatibility data on GitHub

	Desktop						Mobile
	Chrome	Edge	Firefox	Internet Explorer	Opera	Safari	Android webview	Chrome for Android	Firefox for Android	Opera for Android	Safari on iOS	Samsung Internet
get	Chrome Full support 49	Edge Full support 17	Firefox Full support 29	IE No support No	Opera Full support 36	Safari Full support Yes	WebView Android Full support 49	Chrome Android Full support 49	Firefox Android Full support 29	Opera Android Full support 36	Safari iOS Full support Yes	Samsung Internet Android Full support 5.0

Legend

Full support  

Full support

No support  

No support

URLSearchParams.get() by Mozilla Contributors is licensed under CC-BY-SA 2.5.