Php/docs/language.namespaces.dynamic
Namespaces and dynamic language features
(PHP 5 >= 5.3.0, PHP 7, PHP 8)
PHP's implementation of namespaces is influenced by its dynamic nature as a programming language. Thus, to convert code like the following example into namespaced code:
Example #1 Dynamically accessing elements
example1.php:
<?phpclass classname{ function __construct() { echo __METHOD__,"\n"; }}function funcname(){ echo __FUNCTION__,"\n";}const constname = "global";$a = 'classname';$obj = new $a; // prints classname::__construct$b = 'funcname';$b(); // prints funcnameecho constant('constname'), "\n"; // prints global?>
One must use the fully qualified name (class name with namespace prefix). Note that because there is no difference between a qualified and a fully qualified Name inside a dynamic class name, function name, or constant name, the leading backslash is not necessary.
Example #2 Dynamically accessing namespaced elements
<?phpnamespace namespacename;class classname{ function __construct() { echo __METHOD__,"\n"; }}function funcname(){ echo __FUNCTION__,"\n";}const constname = "namespaced";/* note that if using double quotes, "\\namespacename\\classname" must be used */$a = '\namespacename\classname';$obj = new $a; // prints namespacename\classname::__construct$a = 'namespacename\classname';$obj = new $a; // also prints namespacename\classname::__construct$b = 'namespacename\funcname';$b(); // prints namespacename\funcname$b = '\namespacename\funcname';$b(); // also prints namespacename\funcnameecho constant('\namespacename\constname'), "\n"; // prints namespacedecho constant('namespacename\constname'), "\n"; // also prints namespaced?>
Be sure to read the note about escaping namespace names in strings.
